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Velocity-v-Time

Page history last edited by Hailey 3 years, 5 months ago
Speed/Velocity Vs. Time

 

Experiment Questions:

  1. How does the Position/Distance vs. Time graph explain the speed of an object quantitatively?
  2. How does the acceleration of an object affect the slope of the line in a speed/velocity vs. time graph?


 Vocabulary:

  • Speed:
    • The rate at which an object moves
    • Speed only changes when an object speeds up or slows down
      • Speed = Distance ÷ Time
  • Velocity:
    • An objects speed in a specific direction
    • Velocity changes when an object speeds up, slows down, or moves in a different direction
  • Acceleration:
    • the rate at which velocity changes


Part 1: Constant Velocity (air puck experiment)

Finding the velocity at each meter: By finding the slope of the line from the Position/Distance vs. Time graph

Slope = Rise ÷ Run

Slope = (y2- y1) ÷ (x2- x1)

 

Use data from the air puck (Position vs. Time): Constant Speed

Insert Constant Speed Data Table Here Insert Position vs. Time (constant speed) Graph Here
   
  1. First, find the "Rise" which in this case is the "DISTANCE" between each tape mark.  SHOW ALL WORK in your science notebook!
  2. Second, find the "Run" which in this case is the "TIME" it takes for the air puck to travel to each tape mark. SHOW ALL WORK in your science notebook!

 

Now, calculate the speed and enter it in the table above. You may use a calculator. Round to the nearest hundredth. Show the formula you used below:

 

Velocity = Rise÷Run

At Meter 0:

 


=  0 m/s

Velocity = Rise÷Run

From 0 - 1 meter:

 


= 1.61 m/s

Velocity = Rise÷Run

From 1 - 2 meters:

 


= 1.61 m/s

Velocity = Rise÷Run

From 2 - 3 meters:

 


= 1.61 m/s

Velocity =Rise÷Run

from 3 - 4 meters:

 


= 1.61 m/s

 

Now Calculate the AVERAGE SPEED of the air puck from 0 m to 4 m.

Average Speed = Total Distance ÷ Total Time

 

4m ÷  2.48s

 

= 1.61 m/s

 

 

Velocity vs. Time Data Table (constant speed)

Avg. Time (sec)

Velocity (m/s)

0

0

 0.62

 1.61

 1.24

 1.61

 1.86

 1.61

 2.48

 1.61



 

Qualitatively explain what you notice about the graph:
  • Straight (linear)
  • Constant slope (zero slope)
 

Part 2: Increasing Velocity (metal ball with ramp experiment)

Finding the velocity at each meter: By finding the slope of the line from the Position/Distance vs. Time graph

Slope = Rise / Run

Slope = (y2- y1) ÷ (x2- x1)

Use data from the ramp and metal ball (Position vs. Time): Speeding Up

Insert Increasing Speed Data Table Here Insert Position vs. Time (increasing speed) Graph Here

Avg. Time

(sec)

Distance (m)

0

0

1.33

0.75

2.0

1.5

2.6

2.25

3.06

3

  1. First, find the "Rise" which in this case is the "DISTANCE" between each tape mark.  SHOW ALL WORK in your science notebook!
  2. Second, find the "Run" which in this case is the "TIME" it takes for the air puck to travel to each tape mark. SHOW ALL WORK in your science notebook!

 

Now, calculate the speed and enter it in the table above. You may use a calculator. Round to the nearest hundredth. Show the formula you used below:

 

Velocity = Rise÷Run

At Meter 0:

 

 


=  0 m/s

Velocity = Rise÷Run

From 0 - 0.75 meter:

 


= 0.56 m/s

Velocity = Rise÷Run

From 0.75 - 1.5 meters:

 


= 1.12 m/s

Velocity = Rise÷Run

From 1.5 - 2.25 meters:

 


= 1.25 m/s

Velocity =Rise÷Run

from 2.25 - 3 meters:

 


= 1.88 m/s

Calculate the AVERAGE SPEED of the metal ball from 0 m to 3 m.

Average Speed = Total Distance ÷ Total Time

 

3m ÷  3.06s

 

= 0.98m/s

 

 

Velocity vs. Time Data Table (Speeding Up)

Avg. Time (sec)

Velocity (m/s)

 0

0

 1.33

 0.56

 2

 1.12

 2.6

 1.25

 3.06

 1.88

 

 


Qualitatively explain what you notice about the graph:

  • Positive slope

 

Part 3: Decreasing Velocity (metal ball on floor experiment)

Finding the velocity at each meter: By finding the slope of the line from the Position/Distance vs. Time graph

Slope = Rise / Run

Slope = (y2- y1) ÷ (x2- x1)

Use data from the toy car (Position vs. Time): Slowing Down

Insert Decreasing Speed Data Table Here Insert Position vs. Time (decreasing speed) Graph Here

Avg. Time

(sec)

Distance (m)

0

0

1.0

1

2.15

2

3.47

3

5.12

4

  1. First, find the "Rise" which in this case is the "DISTANCE" between each tape mark.  SHOW ALL WORK in your science notebook!
  2. Second, find the "Run" which in this case is the "TIME" it takes for the air puck to travel to each tape mark. SHOW ALL WORK in your science notebook!

 

Now, calculate the speed and enter it in the table above. You may use a calculator. Round to the nearest hundredth. Show the formula you used below:

 

Velocity = Rise÷Run

At Meter 0:

 


=  0 m/s

Velocity = Rise÷Run

From 0 - 1 meter:

 


= 1 m/s

Velocity = Rise÷Run

From 1 - 2 meters:

 


= 0.87 m/s

Velocity = Rise÷Run

From 2 - 3 meters:

 


= 0.76 m/s

Velocity =Rise÷Run

from 3 - 4 meters:

 


= 0.60 m/s

 

Calculate the AVERAGE Speed of the car from 0 m to 4 m.

Average Speed = Total Distance ÷ Total Time

 

4 ÷  5.12

 

=0.78 m/s

 

 

Velocity vs. Time Data Table (Slowing Down)

Avg. Time (sec)

Velocity (m/s)

0

 0

1.0

 1

 2.15

 0.87

3.47

 0.76

5.12

 0.61

 

 


Qualitatively explain what you notice about the graph:

  • Negative slope

 

Part 4: Analyzing Speed vs. Time Graph

 
Time Range
Is the car Accelerating, Decelerating or not Accelerating?
Is the slope Positive, Negative, or Zero Slope?
 
0 to 1 sec
Accelerating
Positive slope
 
1 to 2 sec
Not Accelerating
Zero slope
 
2 to 3 sec
Accelerating
Positive slope
 
3 to 6 sec
Decelerating
Negative slope
 
Time Range
Is the car Accelerating, Decelerating or not Accelerating?
Is the slope Positive, Negative, or Zero Slope?
 
0 to 5 hours
Accelerating Positive slope
 
5 to 10 hours
Accelerating Positive slope
 
10 to 15 hours
Not accelerating Zero slope
 
15 to 20 hours
Decelerating Negative slope
20 to 25 hours Accelerating Positive slope
25 to 30 hours Decelerating Negative slope

Part 5: Calculating Average Speed

  • Speed = Distance ÷ Time
  • Show ALL of your work!!

1.    A car travels 300 miles in 6 hours.  What is the average speed of the car?

Speed = 300m ÷ 6h

Speed = 50 mph

2.    You ride your bike to your friend’s house.  You know that he lives 2500 meters away because you were bored one day and measured it.  It took you 10 minutes to get there.  What was your average speed on the bike?

Speed = 2500m ÷ 10min.

Speed= 250 meters per hour

3.    You are at home and dying for a slurpee so you walk to 7-11 to get one.  It’s 2000 feet away.  After walking 4 minutes you meet up with friends and talk for 3 minutes.  Your friends then join you and it takes you another 5 minutes to get to 7-11.  What is your average speed for you to go from your house to 7-11?

Speed = 2000ft. ÷ 9min.

Speed = 222.22 ft/min

4. Fill in the data table

  • You will need to rearrange the equation Speed = Distance / Time to find the missing information
  • SHOW ALL WORK IN YOUR SCIENCE NOTEBOOK!
Speed
Distance
Time
60 mph 30 miles .5 hours
78 m/s 112 meters 1.44 sec
220 ft/min 3300 feet 15 min
32 cm/s 3136 centimeters 98 sec

Part 6: Summary

Summary
This lesson was different from the one we participated in previously, as there was no actual experimenting taking place.  Instead, the class took the results from the Distance vs. Time experiments and used quantitative facts to prove that the object was speeding up, slowing down, or remaining at a constant speed.  We did this by taking the velocity, or slope, of each portion of the final graph made and compared it to those of the other respective parts.  We found the slope for the distance vs. time graph by using the equation: rise ÷ run.   After calculating the velocity (also known as the slope for this particular experiment) we would then look at each part and see what the differences were. If there were no changes in the slope, as exemplified by the results of the air puck experiment, disregarding the initial beginning when the object went from not moving to doing so, then the object was moving at a constant speed.  If, however, the velocity was increasing from each section of data to the next consecutive portion, then the speed at which the object was moving was also increasing.  Logically, as well as proven using the numbers provided, a slope where the velocity is decreasing would result in the slope decreasing as well. 
 

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